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11042113341293 = 96739111414323
BaseRepresentation
bin1010000010101111000100…
…1111100100011101101101
31110002121121212100002001122
42200223301033210131231
52421403222003410133
635252402110350325
72216523601525106
oct240536117443555
943077555302048
1011042113341293
113577a30128601
1212a40514bb3a5
13621361285b08
142a26266a33ad
1514236d991498
hexa0af13e476d

11042113341293 has 4 divisors (see below), whose sum is σ = 11042125723008. Its totient is φ = 11042100959580.

The previous prime is 11042113341277. The next prime is 11042113341323. The reversal of 11042113341293 is 39214331124011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11042113341293 - 24 = 11042113341277 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11042113341893) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4739771 + ... + 6674552.

It is an arithmetic number, because the mean of its divisors is an integer number (2760531430752).

Almost surely, 211042113341293 is an apocalyptic number.

It is an amenable number.

11042113341293 is a deficient number, since it is larger than the sum of its proper divisors (12381715).

11042113341293 is an equidigital number, since it uses as much as digits as its factorization.

11042113341293 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12381714.

The product of its (nonzero) digits is 15552, while the sum is 35.

The spelling of 11042113341293 in words is "eleven trillion, forty-two billion, one hundred thirteen million, three hundred forty-one thousand, two hundred ninety-three".

Divisors: 1 967391 11414323 11042113341293