1104250031 has 2 divisors, whose sum is σ = 1104250032. Its totient is φ = 1104250030.

The previous prime is 1104250013. The next prime is 1104250057. The reversal of 1104250031 is 1300524011.

Together with previous prime (1104250013) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is an emirp because it is prime and its reverse (1300524011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1104250031 - 2³⁰ = 30508207 is a prime.

It is a super-2 number, since 2×1104250031² = 2438736261927001922, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1104249991 and 1104250009.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1104250061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552125015 + 552125016.

It is an arithmetic number, because the mean of its divisors is an integer number (552125016).

Almost surely, 2^1104250031 is an apocalyptic number.

1104250031 is a deficient number, since it is larger than the sum of its proper divisors (1).

1104250031 is an equidigital number, since it uses as much as digits as its factorization.

1104250031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 1104250031 is about 33230.2577630689. The cubic root of 1104250031 is about 1033.6078682856.

Adding to 1104250031 its reverse (1300524011), we get a palindrome (2404774042).

The spelling of 1104250031 in words is "one billion, one hundred four million, two hundred fifty thousand, thirty-one".