11043113047 has 2 divisors, whose sum is σ = 11043113048. Its totient is φ = 11043113046.

The previous prime is 11043113023. The next prime is 11043113077. The reversal of 11043113047 is 74031134011.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11043113047 is a prime.

It is a super-3 number, since 3×11043113047³ (a number of 31 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11043113017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5521556523 + 5521556524.

It is an arithmetic number, because the mean of its divisors is an integer number (5521556524).

Almost surely, 2^11043113047 is an apocalyptic number.

11043113047 is a deficient number, since it is larger than the sum of its proper divisors (1).

11043113047 is an equidigital number, since it uses as much as digits as its factorization.

11043113047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1008, while the sum is 25.

Adding to 11043113047 its reverse (74031134011), we get a palindrome (85074247058).

The spelling of 11043113047 in words is "eleven billion, forty-three million, one hundred thirteen thousand, forty-seven".