Base | Representation |
---|---|
bin | 10100100100011101… |
… | …10110011110111110 |
3 | 1001111121220211110122 |
4 | 22102032312132332 |
5 | 140104041120220 |
6 | 5023452134542 |
7 | 540443340506 |
oct | 122216663676 |
9 | 31447824418 |
10 | 11043301310 |
11 | 47577237a8 |
12 | 2182467452 |
13 | 106cba8a22 |
14 | 76a942a06 |
15 | 449794425 |
hex | 2923b67be |
11043301310 has 32 divisors (see below), whose sum is σ = 20054466432. Its totient is φ = 4378177440.
The previous prime is 11043301301. The next prime is 11043301327. The reversal of 11043301310 is 1310334011.
It is a super-2 number, since 2×110433013102 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1151957 + ... + 1161503.
It is an arithmetic number, because the mean of its divisors is an integer number (626702076).
Almost surely, 211043301310 is an apocalyptic number.
11043301310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11043301310 is a deficient number, since it is larger than the sum of its proper divisors (9011165122).
11043301310 is a wasteful number, since it uses less digits than its factorization.
11043301310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10568.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 11043301310 its reverse (1310334011), we get a palindrome (12353635321).
The spelling of 11043301310 in words is "eleven billion, forty-three million, three hundred one thousand, three hundred ten".
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