Base | Representation |
---|---|
bin | 1010000010110011100011… |
… | …1011101111010100111111 |
3 | 1110002201201200112200012122 |
4 | 2200230320323233110333 |
5 | 2421413202410234323 |
6 | 35253121313553155 |
7 | 2216565445033331 |
oct | 240547073572477 |
9 | 43081650480178 |
10 | 11043316102463 |
11 | 357849804a8a7 |
12 | 12a43282757bb |
13 | 6214c3506008 |
14 | 2a26dc311451 |
15 | 1423de374ec8 |
hex | a0b38eef53f |
11043316102463 has 2 divisors, whose sum is σ = 11043316102464. Its totient is φ = 11043316102462.
The previous prime is 11043316102433. The next prime is 11043316102499. The reversal of 11043316102463 is 36420161334011.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11043316102463 is a prime.
It is a super-2 number, since 2×110433161024632 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11043316102433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5521658051231 + 5521658051232.
It is an arithmetic number, because the mean of its divisors is an integer number (5521658051232).
Almost surely, 211043316102463 is an apocalyptic number.
11043316102463 is a deficient number, since it is larger than the sum of its proper divisors (1).
11043316102463 is an equidigital number, since it uses as much as digits as its factorization.
11043316102463 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31104, while the sum is 35.
Adding to 11043316102463 its reverse (36420161334011), we get a palindrome (47463477436474).
The spelling of 11043316102463 in words is "eleven trillion, forty-three billion, three hundred sixteen million, one hundred two thousand, four hundred sixty-three".
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