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11043320010854 = 2172314121892597
BaseRepresentation
bin1010000010110011100100…
…1010101001100001100110
31110002201201221220020111212
42200230321022221201212
52421413204410321404
635253121533431422
72216565523202135
oct240547112514146
943081657806455
1011043320010854
11357849a27a27a
1212a432963b572
136214c4273c81
142a26dca4b91c
151423de89806e
hexa0b392a9866

11043320010854 has 16 divisors (see below), whose sum is σ = 18301972807008. Its totient is φ = 4970906193792.

The previous prime is 11043320010847. The next prime is 11043320010913. The reversal of 11043320010854 is 45801002334011.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 11043320010854.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7060945517 + ... + 7060947080.

It is an arithmetic number, because the mean of its divisors is an integer number (1143873300438).

Almost surely, 211043320010854 is an apocalyptic number.

11043320010854 is a deficient number, since it is larger than the sum of its proper divisors (7258652796154).

11043320010854 is a wasteful number, since it uses less digits than its factorization.

11043320010854 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14121892639.

The product of its (nonzero) digits is 11520, while the sum is 32.

Adding to 11043320010854 its reverse (45801002334011), we get a palindrome (56844322344865).

The spelling of 11043320010854 in words is "eleven trillion, forty-three billion, three hundred twenty million, ten thousand, eight hundred fifty-four".

Divisors: 1 2 17 23 34 46 391 782 14121892597 28243785194 240072174149 324803529731 480144348298 649607059462 5521660005427 11043320010854