11043320600537 has 2 divisors, whose sum is σ = 11043320600538. Its totient is φ = 11043320600536.

The previous prime is 11043320600471. The next prime is 11043320600561. The reversal of 11043320600537 is 73500602334011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10083539860681 + 959780739856 = 3175459^2 + 979684^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11043320600537 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11043320600497 and 11043320600506.

It is not a weakly prime, because it can be changed into another prime (11043320600237) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5521660300268 + 5521660300269.

It is an arithmetic number, because the mean of its divisors is an integer number (5521660300269).

Almost surely, 2^{11043320600537} is an apocalyptic number.

It is an amenable number.

11043320600537 is a deficient number, since it is larger than the sum of its proper divisors (1).

11043320600537 is an equidigital number, since it uses as much as digits as its factorization.

11043320600537 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 45360, while the sum is 35.

Adding to 11043320600537 its reverse (73500602334011), we get a palindrome (84543922934548).

The spelling of 11043320600537 in words is "eleven trillion, forty-three billion, three hundred twenty million, six hundred thousand, five hundred thirty-seven".