Base | Representation |
---|---|
bin | 1010000010110011100100… |
… | …1100111001011110010111 |
3 | 1110002201202000000012022112 |
4 | 2200230321030321132113 |
5 | 2421413210033203341 |
6 | 35253121554221235 |
7 | 2216565531206135 |
oct | 240547114713627 |
9 | 43081660005275 |
10 | 11043320600471 |
11 | 357849a642265 |
12 | 12a432988481b |
13 | 6214c441c463 |
14 | 2a26dcb62755 |
15 | 1423de962aeb |
hex | a0b39339797 |
11043320600471 has 2 divisors, whose sum is σ = 11043320600472. Its totient is φ = 11043320600470.
The previous prime is 11043320600423. The next prime is 11043320600537. The reversal of 11043320600471 is 17400602334011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11043320600471 - 26 = 11043320600407 is a prime.
It is a super-3 number, since 3×110433206004713 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11043320600071) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5521660300235 + 5521660300236.
It is an arithmetic number, because the mean of its divisors is an integer number (5521660300236).
Almost surely, 211043320600471 is an apocalyptic number.
11043320600471 is a deficient number, since it is larger than the sum of its proper divisors (1).
11043320600471 is an equidigital number, since it uses as much as digits as its factorization.
11043320600471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12096, while the sum is 32.
Adding to 11043320600471 its reverse (17400602334011), we get a palindrome (28443922934482).
The spelling of 11043320600471 in words is "eleven trillion, forty-three billion, three hundred twenty million, six hundred thousand, four hundred seventy-one".
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