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1104332424007 is a prime number
BaseRepresentation
bin10000000100011111010…
…101111000001101000111
310220120110211021201012011
4100010133111320031013
5121043133100032012
62203153500235051
7142533246503221
oct20043725701507
93816424251164
101104332424007
113963879552aa
1215a03a83ba87
13801a453ab87
143b642a31411
151dad5edc1a7
hex1011f578347

1104332424007 has 2 divisors, whose sum is σ = 1104332424008. Its totient is φ = 1104332424006.

The previous prime is 1104332424001. The next prime is 1104332424029. The reversal of 1104332424007 is 7004242334011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1104332424007 - 231 = 1102184940359 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1104332424007.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1104332424001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552166212003 + 552166212004.

It is an arithmetic number, because the mean of its divisors is an integer number (552166212004).

Almost surely, 21104332424007 is an apocalyptic number.

1104332424007 is a deficient number, since it is larger than the sum of its proper divisors (1).

1104332424007 is an equidigital number, since it uses as much as digits as its factorization.

1104332424007 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16128, while the sum is 31.

Adding to 1104332424007 its reverse (7004242334011), we get a palindrome (8108574758018).

The spelling of 1104332424007 in words is "one trillion, one hundred four billion, three hundred thirty-two million, four hundred twenty-four thousand, seven".