Base | Representation |
---|---|
bin | 10000000100011111010… |
… | …101111000001101000111 |
3 | 10220120110211021201012011 |
4 | 100010133111320031013 |
5 | 121043133100032012 |
6 | 2203153500235051 |
7 | 142533246503221 |
oct | 20043725701507 |
9 | 3816424251164 |
10 | 1104332424007 |
11 | 3963879552aa |
12 | 15a03a83ba87 |
13 | 801a453ab87 |
14 | 3b642a31411 |
15 | 1dad5edc1a7 |
hex | 1011f578347 |
1104332424007 has 2 divisors, whose sum is σ = 1104332424008. Its totient is φ = 1104332424006.
The previous prime is 1104332424001. The next prime is 1104332424029. The reversal of 1104332424007 is 7004242334011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1104332424007 - 231 = 1102184940359 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1104332424007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1104332424001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552166212003 + 552166212004.
It is an arithmetic number, because the mean of its divisors is an integer number (552166212004).
Almost surely, 21104332424007 is an apocalyptic number.
1104332424007 is a deficient number, since it is larger than the sum of its proper divisors (1).
1104332424007 is an equidigital number, since it uses as much as digits as its factorization.
1104332424007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16128, while the sum is 31.
Adding to 1104332424007 its reverse (7004242334011), we get a palindrome (8108574758018).
The spelling of 1104332424007 in words is "one trillion, one hundred four billion, three hundred thirty-two million, four hundred twenty-four thousand, seven".
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