Base | Representation |
---|---|
bin | 1010000010110011101001… |
… | …1001110101111011000011 |
3 | 1110002201210101221222002120 |
4 | 2200230322121311323003 |
5 | 2421413230214133021 |
6 | 35253123554415323 |
7 | 2216566164515313 |
oct | 240547231657303 |
9 | 43081711858076 |
10 | 11043340771011 |
11 | 35784aaa6972a |
12 | 12a4334591543 |
13 | 6214c86623a3 |
14 | 2a27016d3443 |
15 | 1423e15e92c6 |
hex | a0b3a675ec3 |
11043340771011 has 4 divisors (see below), whose sum is σ = 14724454361352. Its totient is φ = 7362227180672.
The previous prime is 11043340771007. The next prime is 11043340771013. The reversal of 11043340771011 is 11017704334011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11043340771011 - 22 = 11043340771007 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11043340771013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1840556795166 + ... + 1840556795171.
It is an arithmetic number, because the mean of its divisors is an integer number (3681113590338).
Almost surely, 211043340771011 is an apocalyptic number.
11043340771011 is a deficient number, since it is larger than the sum of its proper divisors (3681113590341).
11043340771011 is an equidigital number, since it uses as much as digits as its factorization.
11043340771011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3681113590340.
The product of its (nonzero) digits is 7056, while the sum is 33.
The spelling of 11043340771011 in words is "eleven trillion, forty-three billion, three hundred forty million, seven hundred seventy-one thousand, eleven".
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