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11044005040451 is a prime number
BaseRepresentation
bin1010000010110110000111…
…1111110101000101000011
31110002210111200220100110102
42200231201333311011003
52421421110242243301
635253313524153015
72216621511643025
oct240554177650503
943083450810412
1011044005040451
113578810a24139
1212a449ab3876b
136215a3171326
142a2765a0a015
1514242eaaeb6b
hexa0b61ff5143

11044005040451 has 2 divisors, whose sum is σ = 11044005040452. Its totient is φ = 11044005040450.

The previous prime is 11044005040433. The next prime is 11044005040483. The reversal of 11044005040451 is 15404050044011.

11044005040451 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11044005040451 - 214 = 11044005024067 is a prime.

It is not a weakly prime, because it can be changed into another prime (11044005040351) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5522002520225 + 5522002520226.

It is an arithmetic number, because the mean of its divisors is an integer number (5522002520226).

Almost surely, 211044005040451 is an apocalyptic number.

11044005040451 is a deficient number, since it is larger than the sum of its proper divisors (1).

11044005040451 is an equidigital number, since it uses as much as digits as its factorization.

11044005040451 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6400, while the sum is 29.

Adding to 11044005040451 its reverse (15404050044011), we get a palindrome (26448055084462).

The spelling of 11044005040451 in words is "eleven trillion, forty-four billion, five million, forty thousand, four hundred fifty-one".