Base | Representation |
---|---|
bin | 1010000010110110000111… |
… | …1111110101000101000011 |
3 | 1110002210111200220100110102 |
4 | 2200231201333311011003 |
5 | 2421421110242243301 |
6 | 35253313524153015 |
7 | 2216621511643025 |
oct | 240554177650503 |
9 | 43083450810412 |
10 | 11044005040451 |
11 | 3578810a24139 |
12 | 12a449ab3876b |
13 | 6215a3171326 |
14 | 2a2765a0a015 |
15 | 14242eaaeb6b |
hex | a0b61ff5143 |
11044005040451 has 2 divisors, whose sum is σ = 11044005040452. Its totient is φ = 11044005040450.
The previous prime is 11044005040433. The next prime is 11044005040483. The reversal of 11044005040451 is 15404050044011.
11044005040451 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11044005040451 - 214 = 11044005024067 is a prime.
It is not a weakly prime, because it can be changed into another prime (11044005040351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5522002520225 + 5522002520226.
It is an arithmetic number, because the mean of its divisors is an integer number (5522002520226).
Almost surely, 211044005040451 is an apocalyptic number.
11044005040451 is a deficient number, since it is larger than the sum of its proper divisors (1).
11044005040451 is an equidigital number, since it uses as much as digits as its factorization.
11044005040451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6400, while the sum is 29.
Adding to 11044005040451 its reverse (15404050044011), we get a palindrome (26448055084462).
The spelling of 11044005040451 in words is "eleven trillion, forty-four billion, five million, forty thousand, four hundred fifty-one".
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