Base | Representation |
---|---|
bin | 1010000010110110000111… |
… | …1111110101000101100011 |
3 | 1110002210111200220100111121 |
4 | 2200231201333311011203 |
5 | 2421421110242243413 |
6 | 35253313524153111 |
7 | 2216621511643102 |
oct | 240554177650543 |
9 | 43083450810447 |
10 | 11044005040483 |
11 | 3578810a24168 |
12 | 12a449ab38797 |
13 | 6215a317134c |
14 | 2a2765a0a039 |
15 | 14242eaaeb8d |
hex | a0b61ff5163 |
11044005040483 has 2 divisors, whose sum is σ = 11044005040484. Its totient is φ = 11044005040482.
The previous prime is 11044005040451. The next prime is 11044005040511. The reversal of 11044005040483 is 38404050044011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11044005040483 - 25 = 11044005040451 is a prime.
It is not a weakly prime, because it can be changed into another prime (11044005040433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5522002520241 + 5522002520242.
It is an arithmetic number, because the mean of its divisors is an integer number (5522002520242).
Almost surely, 211044005040483 is an apocalyptic number.
11044005040483 is a deficient number, since it is larger than the sum of its proper divisors (1).
11044005040483 is an equidigital number, since it uses as much as digits as its factorization.
11044005040483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 30720, while the sum is 34.
Adding to 11044005040483 its reverse (38404050044011), we get a palindrome (49448055084494).
The spelling of 11044005040483 in words is "eleven trillion, forty-four billion, five million, forty thousand, four hundred eighty-three".
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