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11044315225551 = 317216555200501
BaseRepresentation
bin1010000010110111010001…
…1111000101110111001111
31110002211022022120101102110
42200231310133011313033
52421422224144204201
635253404404355103
72216632266322536
oct240556437056717
943084268511373
1011044315225551
113578960024863
1212a45669a5a93
136216224c6cca
142a2794cb131d
1514244be316d6
hexa0b747c5dcf

11044315225551 has 8 divisors (see below), whose sum is σ = 15591974436144. Its totient is φ = 6929766416000.

The previous prime is 11044315225549. The next prime is 11044315225583. The reversal of 11044315225551 is 15552251344011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11044315225551 - 21 = 11044315225549 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11044315227551) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 108277600200 + ... + 108277600301.

It is an arithmetic number, because the mean of its divisors is an integer number (1948996804518).

Almost surely, 211044315225551 is an apocalyptic number.

11044315225551 is a deficient number, since it is larger than the sum of its proper divisors (4547659210593).

11044315225551 is a wasteful number, since it uses less digits than its factorization.

11044315225551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 216555200521.

The product of its (nonzero) digits is 120000, while the sum is 39.

Adding to 11044315225551 its reverse (15552251344011), we get a palindrome (26596566569562).

The spelling of 11044315225551 in words is "eleven trillion, forty-four billion, three hundred fifteen million, two hundred twenty-five thousand, five hundred fifty-one".

Divisors: 1 3 17 51 216555200501 649665601503 3681438408517 11044315225551