Base | Representation |
---|---|
bin | 1010000010111010010101… |
… | …0000101001110101111111 |
3 | 1110002220102100100021100102 |
4 | 2200232211100221311333 |
5 | 2421430413140234401 |
6 | 35254021515351315 |
7 | 2216661463621403 |
oct | 240564520516577 |
9 | 43086370307312 |
10 | 11045133524351 |
11 | 357923aa23863 |
12 | 12a4754a5253b |
13 | 621722bb5b94 |
14 | 2a2831841103 |
15 | 142498bc056b |
hex | a0ba5429d7f |
11045133524351 has 2 divisors, whose sum is σ = 11045133524352. Its totient is φ = 11045133524350.
The previous prime is 11045133524251. The next prime is 11045133524407. The reversal of 11045133524351 is 15342533154011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11045133524351 - 222 = 11045129330047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11045133524251) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5522566762175 + 5522566762176.
It is an arithmetic number, because the mean of its divisors is an integer number (5522566762176).
Almost surely, 211045133524351 is an apocalyptic number.
11045133524351 is a deficient number, since it is larger than the sum of its proper divisors (1).
11045133524351 is an equidigital number, since it uses as much as digits as its factorization.
11045133524351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108000, while the sum is 38.
Adding to 11045133524351 its reverse (15342533154011), we get a palindrome (26387666678362).
The spelling of 11045133524351 in words is "eleven trillion, forty-five billion, one hundred thirty-three million, five hundred twenty-four thousand, three hundred fifty-one".
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