Base | Representation |
---|---|
bin | 10000000101000111011… |
… | …111110111000010111111 |
3 | 10220122012202222111011122 |
4 | 100011013133313002333 |
5 | 121101023032114333 |
6 | 2203344404141155 |
7 | 142556040060554 |
oct | 20050737670277 |
9 | 3818182874148 |
10 | 1105006129343 |
11 | 3966a3175076 |
12 | 15a1a83977bb |
13 | 80280ca199c |
14 | 3b6a82c2a2b |
15 | 1db25218798 |
hex | 101477f70bf |
1105006129343 has 2 divisors, whose sum is σ = 1105006129344. Its totient is φ = 1105006129342.
The previous prime is 1105006129307. The next prime is 1105006129429. The reversal of 1105006129343 is 3439216005011.
It is a weak prime.
It is an emirp because it is prime and its reverse (3439216005011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1105006129343 - 210 = 1105006128319 is a prime.
It is a super-2 number, since 2×11050061293432 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1105006129243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552503064671 + 552503064672.
It is an arithmetic number, because the mean of its divisors is an integer number (552503064672).
Almost surely, 21105006129343 is an apocalyptic number.
1105006129343 is a deficient number, since it is larger than the sum of its proper divisors (1).
1105006129343 is an equidigital number, since it uses as much as digits as its factorization.
1105006129343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 19440, while the sum is 35.
The spelling of 1105006129343 in words is "one trillion, one hundred five billion, six million, one hundred twenty-nine thousand, three hundred forty-three".
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