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11050540303513 is a prime number
BaseRepresentation
bin1010000011001110011110…
…0001111000010010011001
31110010102101011011010000111
42200303213201320102121
52422023001304203023
635300314221404321
72220242455524064
oct240634741702231
943112334133014
1011050540303513
113580564a06a97
1212a58037096a1
136220a50ba8a9
142a2bc594d8db
151426b36c900d
hexa0ce7878499

11050540303513 has 2 divisors, whose sum is σ = 11050540303514. Its totient is φ = 11050540303512.

The previous prime is 11050540303511. The next prime is 11050540303573. The reversal of 11050540303513 is 31530304505011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11015581774729 + 34958528784 = 3318973^2 + 186972^2 .

It is a cyclic number.

It is not a de Polignac number, because 11050540303513 - 21 = 11050540303511 is a prime.

It is a super-2 number, since 2×110505403035132 (a number of 27 digits) contains 22 as substring.

Together with 11050540303511, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (11050540303511) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5525270151756 + 5525270151757.

It is an arithmetic number, because the mean of its divisors is an integer number (5525270151757).

Almost surely, 211050540303513 is an apocalyptic number.

It is an amenable number.

11050540303513 is a deficient number, since it is larger than the sum of its proper divisors (1).

11050540303513 is an equidigital number, since it uses as much as digits as its factorization.

11050540303513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13500, while the sum is 31.

Adding to 11050540303513 its reverse (31530304505011), we get a palindrome (42580844808524).

The spelling of 11050540303513 in words is "eleven trillion, fifty billion, five hundred forty million, three hundred three thousand, five hundred thirteen".