Search a number
-
+
11050540303511 is a prime number
BaseRepresentation
bin1010000011001110011110…
…0001111000010010010111
31110010102101011011010000102
42200303213201320102113
52422023001304203021
635300314221404315
72220242455524062
oct240634741702227
943112334133012
1011050540303511
113580564a06a95
1212a580370969b
136220a50ba8a7
142a2bc594d8d9
151426b36c900b
hexa0ce7878497

11050540303511 has 2 divisors, whose sum is σ = 11050540303512. Its totient is φ = 11050540303510.

The previous prime is 11050540303493. The next prime is 11050540303513. The reversal of 11050540303511 is 11530304505011.

It is a strong prime.

It is an emirp because it is prime and its reverse (11530304505011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11050540303511 is a prime.

It is a super-2 number, since 2×110505403035112 (a number of 27 digits) contains 22 as substring.

Together with 11050540303513, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11050540303513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5525270151755 + 5525270151756.

It is an arithmetic number, because the mean of its divisors is an integer number (5525270151756).

Almost surely, 211050540303511 is an apocalyptic number.

11050540303511 is a deficient number, since it is larger than the sum of its proper divisors (1).

11050540303511 is an equidigital number, since it uses as much as digits as its factorization.

11050540303511 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4500, while the sum is 29.

Adding to 11050540303511 its reverse (11530304505011), we get a palindrome (22580844808522).

The spelling of 11050540303511 in words is "eleven trillion, fifty billion, five hundred forty million, three hundred three thousand, five hundred eleven".