Base | Representation |
---|---|
bin | 10100100101011001… |
… | …01011010110011011 |
3 | 1001112011122001201202 |
4 | 22102230223112123 |
5 | 140113041320102 |
6 | 5024331504415 |
7 | 540566653553 |
oct | 122254532633 |
9 | 31464561652 |
10 | 11051120027 |
11 | 4761084052 |
12 | 2184bb810b |
13 | 10716b579c |
14 | 76b9ba163 |
15 | 44a2dae02 |
hex | 292b2b59b |
11051120027 has 2 divisors, whose sum is σ = 11051120028. Its totient is φ = 11051120026.
The previous prime is 11051120009. The next prime is 11051120029. The reversal of 11051120027 is 72002115011.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11051120027 - 28 = 11051119771 is a prime.
Together with 11051120029, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 11051119990 and 11051120008.
It is not a weakly prime, because it can be changed into another prime (11051120029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5525560013 + 5525560014.
It is an arithmetic number, because the mean of its divisors is an integer number (5525560014).
Almost surely, 211051120027 is an apocalyptic number.
11051120027 is a deficient number, since it is larger than the sum of its proper divisors (1).
11051120027 is an equidigital number, since it uses as much as digits as its factorization.
11051120027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 140, while the sum is 20.
Adding to 11051120027 its reverse (72002115011), we get a palindrome (83053235038).
The spelling of 11051120027 in words is "eleven billion, fifty-one million, one hundred twenty thousand, twenty-seven".
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