Base | Representation |
---|---|
bin | 10100100101100001… |
… | …00010110001001101 |
3 | 1001112020112112220001 |
4 | 22102300202301031 |
5 | 140113321232303 |
6 | 5024405324301 |
7 | 540611404264 |
oct | 122260426115 |
9 | 31466475801 |
10 | 11052133453 |
11 | 4761706499 |
12 | 2185406691 |
13 | 107197bb4a |
14 | 76bba15db |
15 | 44a43b31d |
hex | 292c22c4d |
11052133453 has 2 divisors, whose sum is σ = 11052133454. Its totient is φ = 11052133452.
The previous prime is 11052133429. The next prime is 11052133457. The reversal of 11052133453 is 35433125011.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8538314409 + 2513819044 = 92403^2 + 50138^2 .
It is an emirp because it is prime and its reverse (35433125011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11052133453 - 221 = 11050036301 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11052133457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5526066726 + 5526066727.
It is an arithmetic number, because the mean of its divisors is an integer number (5526066727).
Almost surely, 211052133453 is an apocalyptic number.
It is an amenable number.
11052133453 is a deficient number, since it is larger than the sum of its proper divisors (1).
11052133453 is an equidigital number, since it uses as much as digits as its factorization.
11052133453 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5400, while the sum is 28.
Adding to 11052133453 its reverse (35433125011), we get a palindrome (46485258464).
The spelling of 11052133453 in words is "eleven billion, fifty-two million, one hundred thirty-three thousand, four hundred fifty-three".
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