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1105451001055 = 5475979729607
BaseRepresentation
bin10000000101100010000…
…000111010010011011111
310220200100210002022102201
4100011202000322103133
5121102430424013210
62203500455232331
7142603051320622
oct20054200722337
93820323068381
101105451001055
113969012a8845
1215a2b13786a7
13803221c439b
143b70b407db9
151db4e2e253a
hex1016203a4df

1105451001055 has 16 divisors (see below), whose sum is σ = 1377727626240. Its totient is φ = 850874355232.

The previous prime is 1105451001049. The next prime is 1105451001077. The reversal of 1105451001055 is 5501001545011.

It is a cyclic number.

It is not a de Polignac number, because 1105451001055 - 23 = 1105451001047 is a prime.

It is a super-2 number, since 2×11054510010552 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 39850939 + ... + 39878668.

It is an arithmetic number, because the mean of its divisors is an integer number (86107976640).

Almost surely, 21105451001055 is an apocalyptic number.

1105451001055 is a deficient number, since it is larger than the sum of its proper divisors (272276625185).

1105451001055 is an equidigital number, since it uses as much as digits as its factorization.

1105451001055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 79729718.

The product of its (nonzero) digits is 2500, while the sum is 28.

Adding to 1105451001055 its reverse (5501001545011), we get a palindrome (6606452546066).

The spelling of 1105451001055 in words is "one trillion, one hundred five billion, four hundred fifty-one million, one thousand, fifty-five".

Divisors: 1 5 47 59 235 295 2773 13865 79729607 398648035 3747291529 4704046813 18736457645 23520234065 221090200211 1105451001055