Base | Representation |
---|---|
bin | 110011011110110000… |
… | …0010010011101100111 |
3 | 101120100122222202010102 |
4 | 1212331200102131213 |
5 | 3302403201243310 |
6 | 122442042014315 |
7 | 10662422406011 |
oct | 1467540223547 |
9 | 346318882112 |
10 | 110553540455 |
11 | 42981656266 |
12 | 195141a739b |
13 | a56b0a9a37 |
14 | 54ca9151b1 |
15 | 2d209d98a5 |
hex | 19bd812767 |
110553540455 has 4 divisors (see below), whose sum is σ = 132664248552. Its totient is φ = 88442832360.
The previous prime is 110553540451. The next prime is 110553540473. The reversal of 110553540455 is 554045355011.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 554045355011 = 191 ⋅2900761021.
It is not a de Polignac number, because 110553540455 - 22 = 110553540451 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (110553540451) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11055354041 + ... + 11055354050.
It is an arithmetic number, because the mean of its divisors is an integer number (33166062138).
Almost surely, 2110553540455 is an apocalyptic number.
110553540455 is a deficient number, since it is larger than the sum of its proper divisors (22110708097).
110553540455 is an equidigital number, since it uses as much as digits as its factorization.
110553540455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22110708096.
The product of its (nonzero) digits is 150000, while the sum is 38.
Adding to 110553540455 its reverse (554045355011), we get a palindrome (664598895466).
The spelling of 110553540455 in words is "one hundred ten billion, five hundred fifty-three million, five hundred forty thousand, four hundred fifty-five".
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