Base | Representation |
---|---|
bin | 1010000011111101110010… |
… | …1111111001110101000000 |
3 | 1110011122011112000122101010 |
4 | 2200333130233321311000 |
5 | 2422230011022113402 |
6 | 35310215001040520 |
7 | 2221202336142042 |
oct | 240773457716500 |
9 | 43148145018333 |
10 | 11063244332352 |
11 | 3585994009983 |
12 | 12a816a186140 |
13 | 62334b072514 |
14 | 2a366cc73a92 |
15 | 142ba8b65a6c |
hex | a0fdcbf9d40 |
11063244332352 has 56 divisors (see below), whose sum is σ = 29672480127616. Its totient is φ = 3637231008768.
The previous prime is 11063244332351. The next prime is 11063244332359. The reversal of 11063244332352 is 25323344236011.
It is a self number, because there is not a number n which added to its sum of digits gives 11063244332352.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11063244332351) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 394650808 + ... + 394678839.
Almost surely, 211063244332352 is an apocalyptic number.
11063244332352 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
11063244332352 is an abundant number, since it is smaller than the sum of its proper divisors (18609235795264).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11063244332352 is an equidigital number, since it uses as much as digits as its factorization.
11063244332352 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 789329735 (or 789329725 counting only the distinct ones).
The product of its (nonzero) digits is 311040, while the sum is 39.
Adding to 11063244332352 its reverse (25323344236011), we get a palindrome (36386588568363).
The spelling of 11063244332352 in words is "eleven trillion, sixty-three billion, two hundred forty-four million, three hundred thirty-two thousand, three hundred fifty-two".
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