Base | Representation |
---|---|
bin | 10100100111000000… |
… | …11011011110000111 |
3 | 1001120010011022101122 |
4 | 22103200123132013 |
5 | 140130024431341 |
6 | 5025534344155 |
7 | 541123166066 |
oct | 122340333607 |
9 | 31503138348 |
10 | 11064686471 |
11 | 47687aa793 |
12 | 218965b05b |
13 | 1074455777 |
14 | 76d70c1dd |
15 | 44b5ba94b |
hex | 29381b787 |
11064686471 has 2 divisors, whose sum is σ = 11064686472. Its totient is φ = 11064686470.
The previous prime is 11064686393. The next prime is 11064686527. The reversal of 11064686471 is 17468646011.
11064686471 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (17468646011) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11064686471 is a prime.
It is a super-3 number, since 3×110646864713 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11064686671) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5532343235 + 5532343236.
It is an arithmetic number, because the mean of its divisors is an integer number (5532343236).
Almost surely, 211064686471 is an apocalyptic number.
11064686471 is a deficient number, since it is larger than the sum of its proper divisors (1).
11064686471 is an equidigital number, since it uses as much as digits as its factorization.
11064686471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 193536, while the sum is 44.
The spelling of 11064686471 in words is "eleven billion, sixty-four million, six hundred eighty-six thousand, four hundred seventy-one".
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