Base | Representation |
---|---|
bin | 10000001000101001010… |
… | …001001011000110000101 |
3 | 10220222222202101201000012 |
4 | 100020221101023012011 |
5 | 121131302221230432 |
6 | 2205212314000005 |
7 | 143051642620526 |
oct | 20105121130605 |
9 | 3828882351005 |
10 | 1108793930117 |
11 | 3982672a3935 |
12 | 15aa84a16005 |
13 | 80735957513 |
14 | 3b94739a84d |
15 | 1dc97a24cb2 |
hex | 1022944b185 |
1108793930117 has 2 divisors, whose sum is σ = 1108793930118. Its totient is φ = 1108793930116.
The previous prime is 1108793930063. The next prime is 1108793930119. The reversal of 1108793930117 is 7110393978011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 902745116641 + 206048813476 = 950129^2 + 453926^2 .
It is a cyclic number.
It is not a de Polignac number, because 1108793930117 - 28 = 1108793929861 is a prime.
Together with 1108793930119, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1108793930119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 554396965058 + 554396965059.
It is an arithmetic number, because the mean of its divisors is an integer number (554396965059).
Almost surely, 21108793930117 is an apocalyptic number.
It is an amenable number.
1108793930117 is a deficient number, since it is larger than the sum of its proper divisors (1).
1108793930117 is an equidigital number, since it uses as much as digits as its factorization.
1108793930117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 285768, while the sum is 50.
The spelling of 1108793930117 in words is "one trillion, one hundred eight billion, seven hundred ninety-three million, nine hundred thirty thousand, one hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •