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11093384353 = 96711471959
BaseRepresentation
bin10100101010011011…
…11001110010100001
31001122010011022111011
422111031321302201
5140204401244403
65032441420521
7541622132302
oct122515716241
931563138434
1011093384353
114782a20947
12219719a741
13107a392b6c
1477345c7a9
1544dd88a6d
hex295379ca1

11093384353 has 4 divisors (see below), whose sum is σ = 11104857280. Its totient is φ = 11081911428.

The previous prime is 11093384329. The next prime is 11093384381. The reversal of 11093384353 is 35348339011.

11093384353 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11093384353 - 25 = 11093384321 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11093384303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5735013 + ... + 5736946.

It is an arithmetic number, because the mean of its divisors is an integer number (2776214320).

Almost surely, 211093384353 is an apocalyptic number.

It is an amenable number.

11093384353 is a deficient number, since it is larger than the sum of its proper divisors (11472927).

11093384353 is an equidigital number, since it uses as much as digits as its factorization.

11093384353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11472926.

The product of its (nonzero) digits is 116640, while the sum is 40.

The spelling of 11093384353 in words is "eleven billion, ninety-three million, three hundred eighty-four thousand, three hundred fifty-three".

Divisors: 1 967 11471959 11093384353