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1109966546669 is a prime number
BaseRepresentation
bin10000001001101111001…
…010010110011011101101
310221010000110212210111212
4100021233022112123231
5121141202413443134
62205524523124205
7143123001655631
oct20115712263355
93833013783455
101109966546669
113988091a7022
1215b151673665
1380891881976
143ba18ddcdc1
151dd15951bce
hex1026f2966ed

1109966546669 has 2 divisors, whose sum is σ = 1109966546670. Its totient is φ = 1109966546668.

The previous prime is 1109966546657. The next prime is 1109966546671. The reversal of 1109966546669 is 9666456699011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 940027202500 + 169939344169 = 969550^2 + 412237^2 .

It is a cyclic number.

It is not a de Polignac number, because 1109966546669 - 228 = 1109698111213 is a prime.

It is a super-2 number, since 2×11099665466692 (a number of 25 digits) contains 22 as substring.

Together with 1109966546671, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1109966546599 and 1109966546608.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1109966546069) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 554983273334 + 554983273335.

It is an arithmetic number, because the mean of its divisors is an integer number (554983273335).

Almost surely, 21109966546669 is an apocalyptic number.

It is an amenable number.

1109966546669 is a deficient number, since it is larger than the sum of its proper divisors (1).

1109966546669 is an equidigital number, since it uses as much as digits as its factorization.

1109966546669 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 113374080, while the sum is 68.

The spelling of 1109966546669 in words is "one trillion, one hundred nine billion, nine hundred sixty-six million, five hundred forty-six thousand, six hundred sixty-nine".