1109999951 has 2 divisors, whose sum is σ = 1109999952. Its totient is φ = 1109999950.

The previous prime is 1109999903. The next prime is 1109999953. The reversal of 1109999951 is 1599999011.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1109999951 is a prime.

Together with 1109999953, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1109999893 and 1109999902.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1109999953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 554999975 + 554999976.

It is an arithmetic number, because the mean of its divisors is an integer number (554999976).

Almost surely, 2^1109999951 is an apocalyptic number.

1109999951 is a deficient number, since it is larger than the sum of its proper divisors (1).

1109999951 is an equidigital number, since it uses as much as digits as its factorization.

1109999951 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 295245, while the sum is 53.

The square root of 1109999951 is about 33316.6617625476. The cubic root of 1109999951 is about 1035.3987902128.

The spelling of 1109999951 in words is "one billion, one hundred nine million, nine hundred ninety-nine thousand, nine hundred fifty-one".