Base | Representation |
---|---|
bin | 10100101011001111… |
… | …00010001001010101 |
3 | 1001122120210200002022 |
4 | 22111213202021111 |
5 | 140213111301003 |
6 | 5033241422525 |
7 | 542033215031 |
oct | 122547421125 |
9 | 31576720068 |
10 | 11100103253 |
11 | 478679a958 |
12 | 219949aa45 |
13 | 107b8a6145 |
14 | 7742cb1c1 |
15 | 44e764738 |
hex | 2959e2255 |
11100103253 has 2 divisors, whose sum is σ = 11100103254. Its totient is φ = 11100103252.
The previous prime is 11100103243. The next prime is 11100103277. The reversal of 11100103253 is 35230100111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10566400849 + 533702404 = 102793^2 + 23102^2 .
It is a cyclic number.
It is not a de Polignac number, because 11100103253 - 28 = 11100102997 is a prime.
It is a super-2 number, since 2×111001032532 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11100103243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550051626 + 5550051627.
It is an arithmetic number, because the mean of its divisors is an integer number (5550051627).
Almost surely, 211100103253 is an apocalyptic number.
It is an amenable number.
11100103253 is a deficient number, since it is larger than the sum of its proper divisors (1).
11100103253 is an equidigital number, since it uses as much as digits as its factorization.
11100103253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90, while the sum is 17.
Adding to 11100103253 its reverse (35230100111), we get a palindrome (46330203364).
The spelling of 11100103253 in words is "eleven billion, one hundred million, one hundred three thousand, two hundred fifty-three".
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