Base | Representation |
---|---|
bin | 1010000110000111001000… |
… | …0111101001011010101001 |
3 | 1110022011022202110200112222 |
4 | 2201201302013221122221 |
5 | 2423331011141201022 |
6 | 35335153054243425 |
7 | 2223646035041432 |
oct | 241416207513251 |
9 | 43264282420488 |
10 | 11100110100137 |
11 | 359a591854963 |
12 | 12b33384b6575 |
13 | 6269749a25b6 |
14 | 2a5369096489 |
15 | 143b153e1242 |
hex | a18721e96a9 |
11100110100137 has 2 divisors, whose sum is σ = 11100110100138. Its totient is φ = 11100110100136.
The previous prime is 11100110100077. The next prime is 11100110100139. The reversal of 11100110100137 is 73100101100111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11058843834256 + 41266265881 = 3325484^2 + 203141^2 .
It is a cyclic number.
It is not a de Polignac number, because 11100110100137 - 26 = 11100110100073 is a prime.
Together with 11100110100139, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (11100110100139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550055050068 + 5550055050069.
It is an arithmetic number, because the mean of its divisors is an integer number (5550055050069).
Almost surely, 211100110100137 is an apocalyptic number.
It is an amenable number.
11100110100137 is a deficient number, since it is larger than the sum of its proper divisors (1).
11100110100137 is an equidigital number, since it uses as much as digits as its factorization.
11100110100137 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21, while the sum is 17.
Adding to 11100110100137 its reverse (73100101100111), we get a palindrome (84200211200248).
The spelling of 11100110100137 in words is "eleven trillion, one hundred billion, one hundred ten million, one hundred thousand, one hundred thirty-seven".
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