111001111103 has 2 divisors, whose sum is σ = 111001111104. Its totient is φ = 111001111102.

The previous prime is 111001111099. The next prime is 111001111129. The reversal of 111001111103 is 301111100111.

It is a weak prime.

It is an emirp because it is prime and its reverse (301111100111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111001111103 - 2² = 111001111099 is a prime.

It is a super-3 number, since 3×111001111103³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111001111153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55500555551 + 55500555552.

It is an arithmetic number, because the mean of its divisors is an integer number (55500555552).

Almost surely, 2^111001111103 is an apocalyptic number.

111001111103 is a deficient number, since it is larger than the sum of its proper divisors (1).

111001111103 is an equidigital number, since it uses as much as digits as its factorization.

111001111103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 11.

Adding to 111001111103 its reverse (301111100111), we get a palindrome (412112211214).

The spelling of 111001111103 in words is "one hundred eleven billion, one million, one hundred eleven thousand, one hundred three".