1110012100411 has 2 divisors, whose sum is σ = 1110012100412. Its totient is φ = 1110012100410.

The previous prime is 1110012100391. The next prime is 1110012100513. The reversal of 1110012100411 is 1140012100111.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1110012100411 - 2¹⁵ = 1110012067643 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1110012100391 and 1110012100400.

It is not a weakly prime, because it can be changed into another prime (1110012140411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555006050205 + 555006050206.

It is an arithmetic number, because the mean of its divisors is an integer number (555006050206).

Almost surely, 2^{1110012100411} is an apocalyptic number.

1110012100411 is a deficient number, since it is larger than the sum of its proper divisors (1).

1110012100411 is an equidigital number, since it uses as much as digits as its factorization.

1110012100411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 1110012100411 its reverse (1140012100111), we get a palindrome (2250024200522).

The spelling of 1110012100411 in words is "one trillion, one hundred ten billion, twelve million, one hundred thousand, four hundred eleven".