Base | Representation |
---|---|
bin | 1010000110000111011110… |
… | …0110111110101111010111 |
3 | 1110022011120011202211211212 |
4 | 2201201313212332233113 |
5 | 2423331203230400043 |
6 | 35335210144252035 |
7 | 2223651233631266 |
oct | 241416746765727 |
9 | 43264504684755 |
10 | 11100202200023 |
11 | 359a62983a972 |
12 | 12b336331101b |
13 | 62698aaab281 |
14 | 2a53773cc5dd |
15 | 143b1d535018 |
hex | a18779bebd7 |
11100202200023 has 2 divisors, whose sum is σ = 11100202200024. Its totient is φ = 11100202200022.
The previous prime is 11100202199969. The next prime is 11100202200089. The reversal of 11100202200023 is 32000220200111.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (32000220200111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11100202200023 - 230 = 11099128458199 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11100202199980 and 11100202200007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11100202200823) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550101100011 + 5550101100012.
It is an arithmetic number, because the mean of its divisors is an integer number (5550101100012).
Almost surely, 211100202200023 is an apocalyptic number.
11100202200023 is a deficient number, since it is larger than the sum of its proper divisors (1).
11100202200023 is an equidigital number, since it uses as much as digits as its factorization.
11100202200023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 14.
Adding to 11100202200023 its reverse (32000220200111), we get a palindrome (43100422400134).
The spelling of 11100202200023 in words is "eleven trillion, one hundred billion, two hundred two million, two hundred thousand, twenty-three".
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