111002400113 has 4 divisors (see below), whose sum is σ = 121093527408. Its totient is φ = 100911272820.

The previous prime is 111002400109. The next prime is 111002400127. The reversal of 111002400113 is 311004200111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 111002400113 - 2² = 111002400109 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (111002400193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5045563631 + ... + 5045563652.

It is an arithmetic number, because the mean of its divisors is an integer number (30273381852).

Almost surely, 2^111002400113 is an apocalyptic number.

It is an amenable number.

111002400113 is a deficient number, since it is larger than the sum of its proper divisors (10091127295).

111002400113 is a wasteful number, since it uses less digits than its factorization.

111002400113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10091127294.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 111002400113 its reverse (311004200111), we get a palindrome (422006600224).

It can be divided in two parts, 111002 and 400113, that added together give a palindrome (511115).

The spelling of 111002400113 in words is "one hundred eleven billion, two million, four hundred thousand, one hundred thirteen".