11100312113 has 4 divisors (see below), whose sum is σ = 12109431408. Its totient is φ = 10091192820.

The previous prime is 11100312089. The next prime is 11100312127. The reversal of 11100312113 is 31121300111.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31121300111 = 11 ⋅2829209101.

It is a cyclic number.

It is not a de Polignac number, because 11100312113 - 2²⁶ = 11033203249 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11100312413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 504559631 + ... + 504559652.

It is an arithmetic number, because the mean of its divisors is an integer number (3027357852).

Almost surely, 2^11100312113 is an apocalyptic number.

It is an amenable number.

11100312113 is a deficient number, since it is larger than the sum of its proper divisors (1009119295).

11100312113 is a wasteful number, since it uses less digits than its factorization.

11100312113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1009119294.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 11100312113 its reverse (31121300111), we get a palindrome (42221612224).

The spelling of 11100312113 in words is "eleven billion, one hundred million, three hundred twelve thousand, one hundred thirteen".