Base | Representation |
---|---|
bin | 10000001001110011000… |
… | …101001101111100011001 |
3 | 10221010012001121220220022 |
4 | 100021303011031330121 |
5 | 121141321232410131 |
6 | 2205535232440225 |
7 | 143124430645604 |
oct | 20116305157431 |
9 | 3833161556808 |
10 | 1110032310041 |
11 | 398842334016 |
12 | 15b16b6a9075 |
13 | 808a2398cc5 |
14 | 3ba23a3b33b |
15 | 1dd1b5e237b |
hex | 1027314df19 |
1110032310041 has 2 divisors, whose sum is σ = 1110032310042. Its totient is φ = 1110032310040.
The previous prime is 1110032310031. The next prime is 1110032310047. The reversal of 1110032310041 is 1400132300111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1001530585225 + 108501724816 = 1000765^2 + 329396^2 .
It is a cyclic number.
It is not a de Polignac number, because 1110032310041 - 222 = 1110028115737 is a prime.
It is not a weakly prime, because it can be changed into another prime (1110032310047) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555016155020 + 555016155021.
It is an arithmetic number, because the mean of its divisors is an integer number (555016155021).
Almost surely, 21110032310041 is an apocalyptic number.
It is an amenable number.
1110032310041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110032310041 is an equidigital number, since it uses as much as digits as its factorization.
1110032310041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 1110032310041 its reverse (1400132300111), we get a palindrome (2510164610152).
The spelling of 1110032310041 in words is "one trillion, one hundred ten billion, thirty-two million, three hundred ten thousand, forty-one".
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