11100401421 has 4 divisors (see below), whose sum is σ = 14800535232. Its totient is φ = 7400267612.

The previous prime is 11100401393. The next prime is 11100401441. The reversal of 11100401421 is 12410400111.

11100401421 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 12410400111 = 3 ⋅4136800037.

It is a cyclic number.

It is not a de Polignac number, because 11100401421 - 2¹³ = 11100393229 is a prime.

It is a super-3 number, since 3×11100401421³ (a number of 31 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11100401421.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11100401441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1850066901 + ... + 1850066906.

It is an arithmetic number, because the mean of its divisors is an integer number (3700133808).

Almost surely, 2^11100401421 is an apocalyptic number.

It is an amenable number.

11100401421 is a deficient number, since it is larger than the sum of its proper divisors (3700133811).

11100401421 is an equidigital number, since it uses as much as digits as its factorization.

11100401421 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3700133810.

The product of its (nonzero) digits is 32, while the sum is 15.

Adding to 11100401421 its reverse (12410400111), we get a palindrome (23510801532).

The spelling of 11100401421 in words is "eleven billion, one hundred million, four hundred one thousand, four hundred twenty-one".