1110100968341 has 2 divisors, whose sum is σ = 1110100968342. Its totient is φ = 1110100968340.

The previous prime is 1110100968329. The next prime is 1110100968343. The reversal of 1110100968341 is 1438690010111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 716308322500 + 393792645841 = 846350^2 + 627529^2 .

It is an emirp because it is prime and its reverse (1438690010111) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1110100968341 is a prime.

It is a Sophie Germain prime.

Together with 1110100968343, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1110100968343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555050484170 + 555050484171.

It is an arithmetic number, because the mean of its divisors is an integer number (555050484171).

Almost surely, 2^{1110100968341} is an apocalyptic number.

It is an amenable number.

1110100968341 is a deficient number, since it is larger than the sum of its proper divisors (1).

1110100968341 is an equidigital number, since it uses as much as digits as its factorization.

1110100968341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 35.

Adding to 1110100968341 its reverse (1438690010111), we get a palindrome (2548790978452).

The spelling of 1110100968341 in words is "one trillion, one hundred ten billion, one hundred million, nine hundred sixty-eight thousand, three hundred forty-one".