11101010000053 has 2 divisors, whose sum is σ = 11101010000054. Its totient is φ = 11101010000052.

The previous prime is 11101009999987. The next prime is 11101010000117. The reversal of 11101010000053 is 35000001010111.

11101010000053 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10119479918769 + 981530081284 = 3181113^2 + 990722^2 .

It is a cyclic number.

It is not a de Polignac number, because 11101010000053 - 2²⁵ = 11100976445621 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11101009999988 and 11101010000042.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11101010004053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550505000026 + 5550505000027.

It is an arithmetic number, because the mean of its divisors is an integer number (5550505000027).

Almost surely, 2^{11101010000053} is an apocalyptic number.

It is an amenable number.

11101010000053 is a deficient number, since it is larger than the sum of its proper divisors (1).

11101010000053 is an equidigital number, since it uses as much as digits as its factorization.

11101010000053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15, while the sum is 13.

Adding to 11101010000053 its reverse (35000001010111), we get a palindrome (46101011010164).

The spelling of 11101010000053 in words is "eleven trillion, one hundred one billion, ten million, fifty-three", and thus it is an aban number.