111010111222013 has 2 divisors, whose sum is σ = 111010111222014. Its totient is φ = 111010111222012.

The previous prime is 111010111222009. The next prime is 111010111222121. The reversal of 111010111222013 is 310222111010111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 64141806464164 + 46868304757849 = 8008858^2 + 6846043^2 .

It is a cyclic number.

It is not a de Polignac number, because 111010111222013 - 2² = 111010111222009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 111010111221982 and 111010111222000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111010111221013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55505055611006 + 55505055611007.

It is an arithmetic number, because the mean of its divisors is an integer number (55505055611007).

Almost surely, 2^{111010111222013} is an apocalyptic number.

It is an amenable number.

111010111222013 is a deficient number, since it is larger than the sum of its proper divisors (1).

111010111222013 is an equidigital number, since it uses as much as digits as its factorization.

111010111222013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 17.

Adding to 111010111222013 its reverse (310222111010111), we get a palindrome (421232222232124).

The spelling of 111010111222013 in words is "one hundred eleven trillion, ten billion, one hundred eleven million, two hundred twenty-two thousand, thirteen".