Base | Representation |
---|---|
bin | 110011101100010110… |
… | …1111110011000010001 |
3 | 101121112111010000222012 |
4 | 1213120231332120101 |
5 | 3304322042104131 |
6 | 122555231552305 |
7 | 11006635251302 |
oct | 1473055763021 |
9 | 347474100865 |
10 | 111010113041 |
11 | 43096350a83 |
12 | 1962108b695 |
13 | a611868229 |
14 | 55314047a9 |
15 | 2d4ab2552b |
hex | 19d8b7e611 |
111010113041 has 2 divisors, whose sum is σ = 111010113042. Its totient is φ = 111010113040.
The previous prime is 111010113031. The next prime is 111010113043. The reversal of 111010113041 is 140311010111.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 64923040000 + 46087073041 = 254800^2 + 214679^2 .
It is a cyclic number.
It is not a de Polignac number, because 111010113041 - 214 = 111010096657 is a prime.
Together with 111010113043, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (111010113043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55505056520 + 55505056521.
It is an arithmetic number, because the mean of its divisors is an integer number (55505056521).
Almost surely, 2111010113041 is an apocalyptic number.
It is an amenable number.
111010113041 is a deficient number, since it is larger than the sum of its proper divisors (1).
111010113041 is an equidigital number, since it uses as much as digits as its factorization.
111010113041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 14.
Adding to 111010113041 its reverse (140311010111), we get a palindrome (251321123152).
The spelling of 111010113041 in words is "one hundred eleven billion, ten million, one hundred thirteen thousand, forty-one".
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