1110111010213 has 2 divisors, whose sum is σ = 1110111010214. Its totient is φ = 1110111010212.

The previous prime is 1110111010201. The next prime is 1110111010331. The reversal of 1110111010213 is 3120101110111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1013229467649 + 96881542564 = 1006593^2 + 311258^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1110111010213 is a prime.

It is a super-2 number, since 2×1110111010213² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1110111010193 and 1110111010202.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1110111014213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555055505106 + 555055505107.

It is an arithmetic number, because the mean of its divisors is an integer number (555055505107).

Almost surely, 2^{1110111010213} is an apocalyptic number.

It is an amenable number.

1110111010213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1110111010213 is an equidigital number, since it uses as much as digits as its factorization.

1110111010213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 1110111010213 its reverse (3120101110111), we get a palindrome (4230212120324).

The spelling of 1110111010213 in words is "one trillion, one hundred ten billion, one hundred eleven million, ten thousand, two hundred thirteen".