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11101130153 = 73915021827
BaseRepresentation
bin10100101011010110…
…11100110110101001
31001122122201211201122
422111223130312221
5140213342131103
65033315425025
7542045022641
oct122553346651
931578654648
1011101130153
114787331433
1221998b5175
13107bb75689
147744b7521
1544e8b8b38
hex295adcda9

11101130153 has 4 divisors (see below), whose sum is σ = 11116152720. Its totient is φ = 11086107588.

The previous prime is 11101130099. The next prime is 11101130263. The reversal of 11101130153 is 35103110111.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11101130153 - 214 = 11101113769 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11101135153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7510175 + ... + 7511652.

It is an arithmetic number, because the mean of its divisors is an integer number (2779038180).

Almost surely, 211101130153 is an apocalyptic number.

It is an amenable number.

11101130153 is a deficient number, since it is larger than the sum of its proper divisors (15022567).

11101130153 is an equidigital number, since it uses as much as digits as its factorization.

11101130153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15022566.

The product of its (nonzero) digits is 45, while the sum is 17.

Adding to 11101130153 its reverse (35103110111), we get a palindrome (46204240264).

The spelling of 11101130153 in words is "eleven billion, one hundred one million, one hundred thirty thousand, one hundred fifty-three".

Divisors: 1 739 15021827 11101130153