1110113402203 has 4 divisors (see below), whose sum is σ = 1195506740848. Its totient is φ = 1024720063560.

The previous prime is 1110113402149. The next prime is 1110113402213. The reversal of 1110113402203 is 3022043110111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1110113402203 is a prime.

It is a super-3 number, since 3×1110113402203³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1110113402213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42696669303 + ... + 42696669328.

It is an arithmetic number, because the mean of its divisors is an integer number (298876685212).

Almost surely, 2^{1110113402203} is an apocalyptic number.

1110113402203 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1110113402203 is a deficient number, since it is larger than the sum of its proper divisors (85393338645).

1110113402203 is an equidigital number, since it uses as much as digits as its factorization.

1110113402203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 85393338644.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 1110113402203 its reverse (3022043110111), we get a palindrome (4132156512314).

The spelling of 1110113402203 in words is "one trillion, one hundred ten billion, one hundred thirteen million, four hundred two thousand, two hundred three".