11101144013023 has 4 divisors (see below), whose sum is σ = 11101152311488. Its totient is φ = 11101135714560.

The previous prime is 11101144013021. The next prime is 11101144013041. The reversal of 11101144013023 is 32031044110111.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 11101144013023 - 2¹ = 11101144013021 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11101144012985 and 11101144013003.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11101144013021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1634658 + ... + 4987423.

It is an arithmetic number, because the mean of its divisors is an integer number (2775288077872).

Almost surely, 2^{11101144013023} is an apocalyptic number.

11101144013023 is a deficient number, since it is larger than the sum of its proper divisors (8298465).

11101144013023 is an equidigital number, since it uses as much as digits as its factorization.

11101144013023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8298464.

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 11101144013023 its reverse (32031044110111), we get a palindrome (43132188123134).

The spelling of 11101144013023 in words is "eleven trillion, one hundred one billion, one hundred forty-four million, thirteen thousand, twenty-three".