11101231341331 has 2 divisors, whose sum is σ = 11101231341332. Its totient is φ = 11101231341330.

The previous prime is 11101231341329. The next prime is 11101231341337. The reversal of 11101231341331 is 13314313210111.

It is a weak prime.

It is an emirp because it is prime and its reverse (13314313210111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11101231341331 - 2¹ = 11101231341329 is a prime.

It is a super-3 number, since 3×11101231341331³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 11101231341329, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 11101231341296 and 11101231341305.

It is not a weakly prime, because it can be changed into another prime (11101231341337) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550615670665 + 5550615670666.

It is an arithmetic number, because the mean of its divisors is an integer number (5550615670666).

Almost surely, 2^{11101231341331} is an apocalyptic number.

11101231341331 is a deficient number, since it is larger than the sum of its proper divisors (1).

11101231341331 is an equidigital number, since it uses as much as digits as its factorization.

11101231341331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 25.

Adding to 11101231341331 its reverse (13314313210111), we get a palindrome (24415544551442).

The spelling of 11101231341331 in words is "eleven trillion, one hundred one billion, two hundred thirty-one million, three hundred forty-one thousand, three hundred thirty-one".