Base | Representation |
---|---|
bin | 10000001001111000111… |
… | …110110111110111000111 |
3 | 10221010102221220122100022 |
4 | 100021320332313313013 |
5 | 121142022103410043 |
6 | 2205553130405355 |
7 | 143130042304361 |
oct | 20117076676707 |
9 | 3833387818308 |
10 | 1110131310023 |
11 | 39889320218a |
12 | 15b19889085b |
13 | 808b9a4c588 |
14 | 3ba32c4bd31 |
15 | 1dd2514a868 |
hex | 10278fb7dc7 |
1110131310023 has 2 divisors, whose sum is σ = 1110131310024. Its totient is φ = 1110131310022.
The previous prime is 1110131309981. The next prime is 1110131310139. The reversal of 1110131310023 is 3200131310111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1110131310023 - 214 = 1110131293639 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1110131309983 and 1110131310010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1110131310823) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555065655011 + 555065655012.
It is an arithmetic number, because the mean of its divisors is an integer number (555065655012).
Almost surely, 21110131310023 is an apocalyptic number.
1110131310023 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110131310023 is an equidigital number, since it uses as much as digits as its factorization.
1110131310023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 1110131310023 its reverse (3200131310111), we get a palindrome (4310262620134).
The spelling of 1110131310023 in words is "one trillion, one hundred ten billion, one hundred thirty-one million, three hundred ten thousand, twenty-three".
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