1110140140433 has 4 divisors (see below), whose sum is σ = 1110142279680. Its totient is φ = 1110138001188.

The previous prime is 1110140140411. The next prime is 1110140140477. The reversal of 1110140140433 is 3340410410111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1110140140433 - 2³⁸ = 835262233489 is a prime.

It is a super-2 number, since 2×1110140140433² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1110140140399 and 1110140140408.

It is not an unprimeable number, because it can be changed into a prime (1110140140133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 258416 + ... + 1512302.

It is an arithmetic number, because the mean of its divisors is an integer number (277535569920).

Almost surely, 2^{1110140140433} is an apocalyptic number.

It is an amenable number.

1110140140433 is a deficient number, since it is larger than the sum of its proper divisors (2139247).

1110140140433 is an equidigital number, since it uses as much as digits as its factorization.

1110140140433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2139246.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 1110140140433 its reverse (3340410410111), we get a palindrome (4450550550544).

The spelling of 1110140140433 in words is "one trillion, one hundred ten billion, one hundred forty million, one hundred forty thousand, four hundred thirty-three".