Base | Representation |
---|---|
bin | 10100101011011110… |
… | …00000001001010111 |
3 | 1001122201111010210202 |
4 | 22111233000021113 |
5 | 140214111424033 |
6 | 5033351411115 |
7 | 542055651125 |
oct | 122557001127 |
9 | 31581433722 |
10 | 11102061143 |
11 | 4787907948 |
12 | 219a083a9b |
13 | 107c110364 |
14 | 77467a915 |
15 | 44e9ee8e8 |
hex | 295bc0257 |
11102061143 has 2 divisors, whose sum is σ = 11102061144. Its totient is φ = 11102061142.
The previous prime is 11102061137. The next prime is 11102061181. The reversal of 11102061143 is 34116020111.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11102061143 - 28 = 11102060887 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11102061043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5551030571 + 5551030572.
It is an arithmetic number, because the mean of its divisors is an integer number (5551030572).
Almost surely, 211102061143 is an apocalyptic number.
11102061143 is a deficient number, since it is larger than the sum of its proper divisors (1).
11102061143 is an equidigital number, since it uses as much as digits as its factorization.
11102061143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 11102061143 its reverse (34116020111), we get a palindrome (45218081254).
The spelling of 11102061143 in words is "eleven billion, one hundred two million, sixty-one thousand, one hundred forty-three".
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