Base | Representation |
---|---|
bin | 1010000110001110100101… |
… | …0101000101100110000010 |
3 | 1110022100111010211211020020 |
4 | 2201203221111011212002 |
5 | 2423344110142042010 |
6 | 35340123341354310 |
7 | 2224046431623252 |
oct | 241435125054602 |
9 | 43270433754206 |
10 | 11102110112130 |
11 | 35a04187aa534 |
12 | 12b37b6268996 |
13 | 626c0315224b |
14 | 2a54b8955962 |
15 | 143bd0ca7470 |
hex | a18e9545982 |
11102110112130 has 32 divisors (see below), whose sum is σ = 26711510842368. Its totient is φ = 2953179744000.
The previous prime is 11102110112101. The next prime is 11102110112213. The reversal of 11102110112130 is 3121101120111.
It is a super-3 number, since 3×111021101121303 (a number of 40 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 461422306 + ... + 461446365.
It is an arithmetic number, because the mean of its divisors is an integer number (834734713824).
Almost surely, 211102110112130 is an apocalyptic number.
11102110112130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11102110112130 is an abundant number, since it is smaller than the sum of its proper divisors (15609400730238).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11102110112130 is a wasteful number, since it uses less digits than its factorization.
11102110112130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 922869082.
The product of its (nonzero) digits is 12, while the sum is 15.
Adding to 11102110112130 its reverse (3121101120111), we get a palindrome (14223211232241).
The spelling of 11102110112130 in words is "eleven trillion, one hundred two billion, one hundred ten million, one hundred twelve thousand, one hundred thirty".
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