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111021110100013 is a prime number
BaseRepresentation
bin11001001111100100011101…
…110101001000000000101101
3112120002111220001100101210011
4121033210131311020000231
5104022432213141200023
61032042221025013221
732246003414252641
oct3117443565100055
9476074801311704
10111021110100013
1132413874378733
1210550775184211
1349c4326c20829
141d5b643c7ac21
15cc7da93c350d
hex64f91dd4802d

111021110100013 has 2 divisors, whose sum is σ = 111021110100014. Its totient is φ = 111021110100012.

The previous prime is 111021110100001. The next prime is 111021110100067. The reversal of 111021110100013 is 310001011120111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 80540088694569 + 30481021405444 = 8974413^2 + 5520962^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-111021110100013 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 111021110099966 and 111021110100002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111021110100413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55510555050006 + 55510555050007.

It is an arithmetic number, because the mean of its divisors is an integer number (55510555050007).

Almost surely, 2111021110100013 is an apocalyptic number.

It is an amenable number.

111021110100013 is a deficient number, since it is larger than the sum of its proper divisors (1).

111021110100013 is an equidigital number, since it uses as much as digits as its factorization.

111021110100013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 111021110100013 its reverse (310001011120111), we get a palindrome (421022121220124).

The spelling of 111021110100013 in words is "one hundred eleven trillion, twenty-one billion, one hundred ten million, one hundred thousand, thirteen".